Author Topic: Akula0083 30 Watt Self Running Generator. (Read 1275921 times)

Hoppy · « **Reply #405 on:** March 24, 2014, 09:13:29 PM »

Quote from: Grumage on March 24, 2014, 08:41:12 PM

Good evening Hoppy.

I have attached a revised copy of your clip showing what I feel are the two capacitors you are referring to.

Cheers Grum.

Evening Grum,

Are you referring to the cap connected to pin 'CT' of the TL494 chip? I had discounted this as it looks way too large to be a cap needed for TL494 external components.

Regards
Hoppy

Grumage · « **Reply #406 on:** March 24, 2014, 10:41:29 PM »

Quote from: Hoppy on March 24, 2014, 09:13:29 PM

Evening Grum,

Are you referring to the cap connected to pin 'CT' of the TL494 chip? I had discounted this as it looks way too large to be a cap needed for TL494 external components.

Regards
Hoppy

Dear Hoppy.

Sorry a bit of missinfo !! They are actually the capacitors associated with the Voltage regulator. C6 and C13, being 100uF and 100 nF respectively.

Cheers Grum.

Grumage · « **Reply #407 on:** March 24, 2014, 10:56:26 PM »

Dear All.

I have just finished chatting with T-1000. He passed on this fairly simplified control circuit which might help those, like me, who have a bit less electronic skills.

I am also providing an eBay link for 1 W LED's that will be just right for a starting load.

http://www.ebay.co.uk/itm/10-1W-High-Power-Pure-White-LED-Bright-Light-Lamp-Bulb-Bead-DIY-/251088281787?pt=UK_BOI_Electrical_Components_Supplies_ET&hash=item3a760720bb

Keep on trucking !!

Cheers Grum.

MileHigh · « **Reply #408 on:** March 24, 2014, 11:14:16 PM »

Grumage:

Quote

I am also providing an eBay link for 1 W LED's that will be just right for a starting load.

Do you know if any of the replicators have a digital storage oscilloscope with math functions? I believe that a good PC-based digital oscilloscope can also do math functions.

Without the ability to compute the real-time-sampled voltage and current going into the LEDs you can't measure the power going into the LEDs. The frequency of the pulse waveform will give you a sense for how high the minimum sampling rate has to be. The higher the pulse frequency the higher the minimum sampling rate.

Plan B involves choosing the proper value of resistor and replacing the entire LED array with the resistor. Then all that you need is a true-RMS multimeter. The assumption is that the bandwidth in the pulse waveform will not be too high for the multimeter. But that should also be verified to ensure that you are making a correct power measurement.

MileHigh

Hoppy · « **Reply #409 on:** March 24, 2014, 11:51:07 PM »

Quote from: Grumage on March 24, 2014, 10:41:29 PM

Dear Hoppy.

Sorry a bit of missinfo !! They are actually the capacitors associated with the Voltage regulator. C6 and C13, being 100uF and 100 nF respectively.

Cheers Grum.

Thanks Grum. I agree that the caps are probably C6 and C13. However, I would like to see a close-up of C13 as it still appears to be way too large for a 100nF. I suspect that its an electrolytic and possibly a super cap.

Grumage · « **Reply #410 on:** March 25, 2014, 12:10:14 AM »

Quote from: MileHigh on March 24, 2014, 11:14:16 PM

Grumage:

Do you know if any of the replicators have a digital storage oscilloscope with math functions? I believe that a good PC-based digital oscilloscope can also do math functions.

Without the ability to compute the real-time-sampled voltage and current going into the LEDs you can't measure the power going into the LEDs. The frequency of the pulse waveform will give you a sense for how high the minimum sampling rate has to be. The higher the pulse frequency the higher the minimum sampling rate.

Plan B involves choosing the proper value of resistor and replacing the entire LED array with the resistor. Then all that you need is a true-RMS multimeter. The assumption is that the bandwidth in the pulse waveform will not be too high for the multimeter. But that should also be verified to ensure that you are making a correct power measurement.

MileHigh

Dear MileHigh.

Although my Scope is pretty sophisticated it does not have a maths function. Itsu on the other hand does have that facility. He is prototyping the control circuit as I write !!

My gut feeling tells me that a resistive load would not create the same circumstances as LED's would. Because they also have minute capacitance and are for the most part forward (one way) conducting.

Cheers Grum.

MileHigh · « **Reply #411 on:** March 25, 2014, 12:55:28 AM »

It's great to hear that Itsu is going to build the circuit. I love his scope and he does great builds. It almost looks like this is basically a "solid state Bedini" setup with a bunch of "extra" components. If that is confirmed to be the case then when the MOSFET switches off the main L1 in the transformer (in tandem with the battery) discharges its stored magnetic energy as a current pulse. If you look at the schematic and follow the current loop it takes a "loopy" pathway through a whole bunch of components. Also if that is the case it won't matter very much if the load is an LED array or a resistance, they both will dissipate a somewhat similar amount of power. To be more specific, the higher the value of the load resistance proportionally more power will be dissipated in the load resistance. It all depends on the relative resistance of every component in the current loop.

It should be an interesting set of tests.

T-1000 · « **Reply #412 on:** March 25, 2014, 01:07:44 AM »

Quote from: MileHigh on March 25, 2014, 12:55:28 AM

It's great to hear that Itsu is going to build the circuit. I love his scope and he does great builds. It almost looks like this is basically a "solid state Bedini" setup with a bunch of "extra" components. If that is confirmed to be the case then when the MOSFET switches off the main L1 in the transformer (in tandem with the battery) discharges its stored magnetic energy as a current pulse. If you look at the schematic and follow the current loop it takes a "loopy" pathway through a whole bunch of components. Also if that is the case it won't matter very much if the load is an LED array or a resistance, they both will dissipate a somewhat similar amount of power. To be more specific, the higher the value of the load resistance proportionally more power will be dissipated in the load resistance. It all depends on the relative resistance of every component in the current loop.

It should be an interesting set of tests.

There is even more than this in circuit

Here is how I see it:

MOSFET ON - pulse goes over L2 and charges capacitor C4. The load is getting disconnected from power

MOSFET OFF - BEMF kicks in with opposite direction (C3 gets charge) from primary L1 and it goes in series with charged capacitor C4 all way back to C11 which gets charged with voltage kick from BEMF+current from C4. Also when C4 gets discharged the remaining BEMF gets over diodes and L2 back to C11->R1 to complete path. The load takes the residue of BEMF pulse and comes back to discharge C3+C11 over L1.

P.S> The function of C5 + R5 is still not clear to me in original circuit. Perhaps the intention was to manipulate duty cycle with this feedback path?

Cheers!

cheappower2012 · « **Reply #413 on:** March 25, 2014, 01:37:38 AM »

Hoopy are you implying that the sharkhead's(Akula) device is a fraud,lol.
Akula was influenced by Westley's split yoke device which was never shown to work,
monkey see,monkey copy.In the past I seen at least 100 of this pulse at high frequencies
type of devices, none were overunity,none were self running.A large amount were errors
in measurement,not flat out frauds
like it seems the Russians keep pumping out.Normally I find this whole thing amusing,its a future train wreck,
unfortunately a lot of people will get very discouraged.

MileHigh · « **Reply #414 on:** March 25, 2014, 01:44:07 AM »

Depending on what frequency the oscillator runs at, it's possible that C3 provides enough low-pass filtering (i.e.; it filters out the high-frequency spikes) so that the voltage at the top of the LED array is mostly DC with a moderate voltage ripple.

For C5 and R5, you can say that C5 is like a high-pass filter, and what flows through R5 is mostly DC with a moderate voltage ripple. So it could be that C5 and R5 are there just so you can put your multimeter across R5 and measure the average DC current flowing through the LED array.

You notice that if the above two conditions are true, the voltage at the top of the LED array is near-DC, and the average current through R5 is near-DC (to be verified with a scope) then you can make a decent measurement of the power flowing through the LED array with multimeters alone.

Anyway, no more predictions because it's too difficult to do and the scope may show a different story.

MenofFather · « **Reply #415 on:** March 25, 2014, 08:28:00 AM »

Quote from: T-1000 on March 25, 2014, 01:07:44 AM

P.S> The function of C5 + R5 is still not clear to me in original circuit. Perhaps the intention was to manipulate duty cycle with this feedback path?

How I understand, this function change duty cycle depending on load. Wihout load 0 precents duty cycle, with small load let say 20 precents, with big lload let say 60 precents.

Hoppy · « **Reply #416 on:** March 25, 2014, 09:47:51 AM »

Quote from: cheappower2012 on March 25, 2014, 01:37:38 AM

Hoopy are you implying that the sharkhead's(Akula) device is a fraud,lol.
Akula was influenced by Westley's split yoke device which was never shown to work,
monkey see,monkey copy.In the past I seen at least 100 of this pulse at high frequencies
type of devices, none were overunity,none were self running.A large amount were errors
in measurement,not flat out frauds
like it seems the Russians keep pumping out.Normally I find this whole thing amusing,its a future train wreck,
unfortunately a lot of people will get very discouraged.

Although to me this circuit as it stands is clearly never going to self-run and in this respect is a future train crash, I do not feel that its a waste of time to build. Akula appears to have designed what he feels is an efficient LED driver operating from a low voltage battery source with energy conservation in mind, so I do see it worthwhile for those interested, building this circuit just to see if there is any efficiency to be had over a more conventional LED driver.

MenofFather · « **Reply #417 on:** March 25, 2014, 10:44:08 AM »

Quote from: Grumage on March 24, 2014, 10:56:26 PM

Dear All.

I have just finished chatting with T-1000. He passed on this fairly simplified control circuit which might help those, like me, who have a bit less electronic skills.

I am also providing an eBay link for 1 W LED's that will be just right for a starting load.

http://www.ebay.co.uk/itm/10-1W-High-Power-Pure-White-LED-Bright-Light-Lamp-Bulb-Bead-DIY-/251088281787?pt=UK_BOI_Electrical_Components_Supplies_ET&hash=item3a760720bb

Keep on trucking !!

Cheers Grum.

I try that schematic without feedback. Then if wounded primary and on top secondary, then addading secondary, you get input current about 5 amps. And changing freenquency not help. So if you want try schematic with 45-50 duty cycle and wihout feedback, then wound primary and secondary coils on diferent sides of core, they must not intervealed be, not wound one on top other, then maybe you get selfrunning.

T-1000 · « **Reply #418 on:** March 25, 2014, 09:15:31 PM »

Quote from: MenofFather on March 25, 2014, 10:44:08 AM

I try that schematic without feedback. Then if wounded primary and on top secondary, then addading secondary, you get input current about 5 amps.

What frequency and load you are applying? for 15T primary, LEDs on load and high resonant frequency it should be low...
Also the duty cycle must be not 50% - less than 20%.

verpies · « **Reply #419 on:** March 26, 2014, 05:08:46 PM »

Quote from: T-1000 on March 25, 2014, 01:07:44 AM

The function of C5 + R5 is still not clear to me in original circuit. Perhaps the intention was to manipulate duty cycle with this feedback path?

On this schematic, the voltage signal taken from R5 must become negative to activate the 2^nd error amplifier of the TL494 (pins 15 & 16) via R7.
If R5 is non-inductive then this would mean that the current through these load LEDs needs to flow in reverse for this to occur.

The 1^st error amplifier of the TL494 (pins 1 & 2) is configured to react only to quickly falling edges at R5 (via R7). The R11 pot determines how steep these falling edges need to be in order to trigger this 1^st error amplifier.

Activation of either one of these error amplifiers will immediately decrease the output duty cycle of the TL494.

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Author Topic: Akula0083 30 Watt Self Running Generator. (Read 1275921 times)

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