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Hi @all,

probably with 10KV it's easy make a elettrostatic motor , but the COP is not > 1.

A turning dielectric without perfect symmetry in an electrostatic fields connected to a voltage source will have an oscillating capacity and an oscillating charge - and there will be of course an oscillating current.
If we assume that there are pretty no perfect HV voltage sources - and that the response of the HV voltage source regulation circuit is not infinite fast - this regulation circuit might be responsilble for re-gauge.
Operating that thing from a charged cap would give immediate proof of concept.

If the thing turns from a state of higher capacity to a lower capacity state - it releases charge  to the supply - acts as source. If it turns from lower capacity state to higher capacity state - it draws current from the supply.

If u assume that the output impedance of the supply changes with output voltage (whats for sure) -  you can assume that 10kv is the threshold where the electrostatic force which keeps the thing on track against the water (the thing is frozen in its electrical minimum - but not balanced from swimming point of view) is exceeded.

So without proper current/voltage measurements _ or operation from a charged cap _ this is just another funny half-mechanical HV oscillator - powered from the negative resistance of the HV supply - which finally gets his power from mains.

(And we havent talked about the voltage supply internal losses yet)

The oscillation energy is transfered between the misbalanced wheel(potential energy) - and the charge.
If the output resistance of the voltage supply increases >=10kv - the mechnical potential energy stored is transfered into mechanical inertia. The resulting turn releases charge to the supply - means a negative current which results in a down regulating response of the HV voltage source - which adds an additional pull. If the wheel reaches the point of minimum capacity (all delta charge released) the current to the supply changes from minus to zero and the regulation circuit has to backup with a positive pulse to maintain the output voltage. If the involved time-constants fit - this pulse (which can also be seen as time interval with low output impedance) can be enough to move the wheel back to the state of maximum potential energy) - we have a perfect motor;-))

A sufficient HV cap in parallel to the device under test - as well as the experiment carried out 2 times with two different power supplies would wipe away any doubt on my side.

Several threads about this rotor already exist on this forum.

The rotor you see operating in the video is not "overunity" because its spinning in open air. Large voltage potentials in air can ionize air molecules at the tips of sharp conductors. This causes a thrust onto the vaned rotor blades. I have discussed this with Dr. Turtur and have read his publications, where he mentions ionic wind influence with rotors exposed to air. The power loss is great when operating at ambient pressure. In fact, power loss becomes unacceptably high even at voltages below the point of rotation.

The rotor must be placed inside a high-vacuum dielectric to stop the influence of ion thrusts. There and only then will the rotor allegedly operate with a COP greater than 1. Dr. Turtur's experiments and calculations conclude a much higher power output than power loss (over 50x) but only inside a laboratory vacuum chamber.

The technology may be revolutionary if its real but there is a very big catch. The power density from vacuum energy alone is very small; therefore a very large metal vacuum chambers and expensive rotary and turbo pumps are necessary. The power density is such that a machine capable of powering your home will require a vacuum chamber similar in size to NASA's.

http://www.nasa.gov/multimedia/imagegallery/image_feature_1281.html

We can imagine such structures costing tens to hundreds of millions to build. Despite this, I'm still very interested in the technology.